00:01
Hello students, in this question we have four parts.
00:05
First we need to calculate part a in which we have to determine the value of r to set voh is 1 .65 volt.
00:17
Now assuming mos is in saturation region we have lp is equal to mu p cox omega by l vsg minus vth whole square.
00:45
Now substituting the values we get 400 into 10 to the power minus 6 into 3 by 0 .3 bracket 0 .7 minus 0 .5 to the whole square.
01:01
When voh is equal to 1 .65 volt then voh minus 0 is equal to ibr and here we can write ib is equal to 1 .65 upon r.
01:21
Now putting this value in here we can write 1 .65 divided by r.
01:28
Now this can be written as 1 .65 divided by r is equal to 160 mu a which is equal to ib.
01:39
Now this can be written as r is equal to 1 .65 divided by 160 that is equal to r is equal to 10 .3 kilo ohm.
01:55
For part b we have to find voltage transfer characteristic that is vtc.
02:12
Now to find this we have vpo upon vi is equal to minus gm rb.
02:22
Now substituting the values we get it is equal to 1 .6 into 10 to the power minus 3 into 10 .3 that is we get v0 upon vi is equal to 16 .48.
02:42
Now moving to part c in which we have to find how we reduce this vm value...