00:01
Hello student in this question it is given that given that the period of moon, that is tm, tm is 27 .3 days.
00:14
27 .3 days and mean distance from moon center to center of earth, that is r1 is 3 .9 multiplied by 10 to 5 km.
00:31
Now by using kepler's law, using kepler's law, kepler's law, we know that t1 square is directly proportional to r1 cube.
00:47
T1 square is directly proportional to rr1 cube or t1 square is equals to a r1 cube and the value of a is t1 squared divided by r1 cube which is 2 27 .232 .2 .2 .2 .2 .2 .2 .2 .2 .2 .2 .2 .2.
01:14
2 .2 .2 .2 .2.
01:14
Multip 2 .2.
01:20
Depets.
01:21
Depend to the first.
01:29
Satellite.
01:30
Destance of satellite to the center of earth r1 is 6 .5 .5.
01:38
0 .70 multiplied by 10 to the power 3 km.
01:45
Now again by using kepler's law, using kepler's law, using kepler's law, we know that t2 squared is equals to a r2 cube.
02:04
So now putting the values, t2 square is equals to 27 .3 square divided by 3 .9 multiplied by 10 to the power 5 whole cube 10 to the power 5 whole cube so the value is 6 .70 multiplied by 10 to the power 3 whole cube now by using equation 1 using equation equation 1 using first equation taking square root on both side taking square root on both sides we get t2 is equal to 27 .3 divided by 3 .9 3 .9 multiply by 10 to the power 5 root of 3 .9 multiply by 3 .9 multiply by 10 to the power 5 multiply by 6 .70 multiplied by 10 to the power 3 and root of 6 .7 multiplied by 10 to the power 3.
03:37
Further the value of t2 is equal to 182 .91 multiplied by 182 .91 multiplied by 182 .91 multiplied by 10 to the power 3 multiplied by 182 .91 multiplied by 10 to the power 3, 8 .19 multiplied by 10 to the power 1 divided by 3 .9 multiplied by 10 to the power 5 multiply by 6...