00:01
Hi, now we are going to find the cooling constant.
00:03
The given temperature of reservoir is 60 degree fahrenheit.
00:18
So we have tr is equal to 60 degree fahrenheit.
00:23
And after 20 seconds, the temperature will be 90 degree fahrenheit.
00:27
So, t of 20 is equal to 90 degree fahrenheit.
00:33
After one minute, it will be 70 degree fahrenheit.
00:36
So we have t of 60 is equal to 70 degree fahrenheit.
00:43
Now we are going to use the formula f of t is equal to tr plus t1 minus tr into e power minus kt.
00:57
In this formula we are going to substitute the corresponding values.
01:01
Then we get f of t is equal to 60 plus t1 minus 60.
01:08
Into e power minus kt.
01:11
Now put t is equal to 20, then we get f of 20 is equal to 60 plus t1 minus 60 into e power minus 20k is equal to 90.
01:28
From this we get t1 minus 60 into e power minus 20k is equal to 30.
01:37
And i label this one as equation number 1.
01:41
And next put t is equal to 60.
01:44
Then we get f of 60 is equal to 60 plus t1 minus 60 into e power minus 60 k is equal to 70.
01:57
From this we get t1 minus 60 into e power minus 60 k is equal to 10.
02:05
And i label this one as equation number number...