00:01
In the question it is given that we have mass is equal to 10 kg, mass that is m is equal to 10 kg and we have k is equal to 250 kilogram per second square.
00:18
Now the solution is given by, the solution is y of t is equal to c1 cos of omega t plus c2 sin of omega t.
00:42
Here omega is equal to under root of k by m and it is the frequency of oscillation.
01:00
It is the frequency of oscillation.
01:02
Therefore on putting the values omega will be equal to under root of 250 upon 10.
01:09
So this is equal to under root 25 since 0 will get cancelled by 0 and we will have under root 25 which is equal to 5 second inverse.
01:20
So therefore y of t will be equal to c1 cos of 5t plus c2 sin of 5t.
01:36
Now applying initial values we will get y of 0 will be equal to 0 .3 m and y dash of 0 is equal to minus 0 .1 meter upon second.
01:51
So y of 0 will be equal to c1 cos of 0 plus c2 sin of 0.
02:02
This is further equal to 0 .3 m is equal to c1 the value of cos 0 is 1 plus c2 the value of sin 0 is 0.
02:12
So therefore we will have 0 .3 m is equal to c1...