Question

The drawing (not to scale) shows one alignment of the sun, earth, and moon. The gravitational force $\vec{F}_{SM}$ that the sun exerts on the moon is perpendicular to the force $\vec{F}_{EM}$ that the earth exerts on the moon. The masses are: mass of sun = $1.99 \times 10^{30}$ kg, mass of earth = $5.98 \times 10^{24}$ kg, mass of moon = $7.35 \times 10^{22}$ kg. The distances shown in the drawing are $r_{SM} = 1.50 \times 10^{11}$ m and $r_{EM} = 3.85 \times 10^8$ m. Determine the magnitude of the net gravitational force on the moon.

          The drawing (not to scale) shows one alignment of the sun, earth, and moon. The gravitational force $\vec{F}_{SM}$ that the sun exerts on the moon is perpendicular to the force $\vec{F}_{EM}$ that the earth exerts on the moon. The masses are: mass of sun = $1.99 \times 10^{30}$ kg, mass of earth = $5.98 \times 10^{24}$ kg, mass of moon = $7.35 \times 10^{22}$ kg. The distances shown in the drawing are $r_{SM} = 1.50 \times 10^{11}$ m and $r_{EM} = 3.85 \times 10^8$ m. Determine the magnitude of the net gravitational force on the moon.

The drawing (not to scale) shows one alignment of the sun, earth, and moon. The gravitational force F⃗SM that the sun exerts on the moon is perpendicular to the force F⃗EM that the earth exerts on the moon. The masses are: mass of sun = 1.99 × 10^30 kg, mass of earth = 5.98 × 10^24 kg, mass of moon = 7.35 × 10^22 kg. The distances shown in the drawing are rSM = 1.50 × 10^11 m and rEM = 3.85 × 10^8 m. Determine the magnitude of the net gravitational force on the moon.

Added by Jesus C.

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