00:02
According to the question, we can set up the null hypothesis as the three group means are the same and it is given total sum of squares is 464.
00:18
So, sum of squares 2 -2 treatment can be calculated using the given information that t1 square by l1 plus t2 square by n2 plus t3 square by n3 minus capital g square by l.
00:40
All these values are given and on substitution this becomes 16 square by 8 plus 24 square by 6 plus 32 square by 4 minus 72 square by 8.
01:01
So, this becomes 96.
01:04
Then we can obtain error sum of squares which is obtained by total sum of squares minus sum of squares 2 -2 treatment.
01:13
Substituting the corresponding values this becomes 368.
01:19
Now, we have to obtain the degrees of freedom corresponding to treatment.
01:24
As there are three treatments the degrees of freedom is k minus 1 which is 3 minus 1 equal to 2.
01:32
Now, we have to obtain the degrees of freedom corresponding to error...