00:01
This problem asks us to write the net ionic equation for three different reactions.
00:07
Now, as a reminder, when you write out net ionic reactions, we're only going to include the important species in the reaction.
00:15
Those are the species that do the reaction.
00:18
The other species that get cancelled out are going to be the spectator species.
00:23
And this first one, i'll walk through more slowly so you can see what i mean by that.
00:27
So whenever we have an aqueous solution like this, it's going to dissociate completely.
00:38
And the things that dissociate completely are strong electrolytes.
00:41
And for our purposes in this problem, if we have an aqueous, it's going to be a strong electrolyte.
00:47
However, there are solubility rules that you need to know and use in order to identify strong electrolytes in different problems.
00:56
If it's a strong electrolyte, it's going to split up into its individual ions.
01:02
So silver splits up into its two different ions, and then nitrate splits up into its ions as well.
01:10
Notice that i'm moving that coefficient in front to indicate that this two is showing we have two silvers as well as two nitrates.
01:22
Going on to the sodium, we have two of those sodiums.
01:26
The two comes out front as well.
01:28
Well to show that both of those sodiums dissociated.
01:32
Another way that we could show this is one sodium dissociates and another sodium dissociates.
01:40
And the chromate right afterwards is going to stay together as a package.
01:50
This is because it is a polyatomic ion.
01:54
At the other side here, since this silver chromate here is a solid.
02:00
It is not going to dissociate.
02:02
This is going to be the important piece of the reaction.
02:05
This is the precipitate that forms.
02:07
We get silver and chromate.
02:13
And that's solid.
02:15
Then we get our two sodiums again and our two nitrates.
02:22
And now we go through and cancel out the spectator species...