Texts: Two B85 V-belts are used on a 5.4 in. drive pulley, rotating at 1200 rev/min and driving a 16 in. pulley. Find the power capacity that the drive pulley can transmit based on a service factor of 1.25 and find the distance between centers.
Solution:
Given:
D1 = 5.4 in. (diameter of drive pulley)
N1 = 1200 rev/min (rotational speed of drive pulley)
D2 = 16 in. (diameter of driven pulley)
SF = 1.25 (service factor)
To find the power capacity that the drive pulley can transmit, we can use the formula:
P = (T1 * N1) / 63025
Where:
P = power capacity (in horsepower)
T1 = tension in the belt (in pounds)
N1 = rotational speed of drive pulley (in revolutions per minute)
To find the tension in the belt, we can use the formula:
T1 = (SF * HP) / (RPM * K)
Where:
SF = service factor
HP = horsepower
RPM = rotational speed of drive pulley
K = constant (dependent on the type of belt)
To find the distance between centers, we can use the formula:
C = 2 * sqrt((D1/2)^2 + (D2/2)^2)
Where:
C = distance between centers
D1 = diameter of drive pulley
D2 = diameter of driven pulley
Given values:
D1 = 5.4 in.
N1 = 1200 rev/min
D2 = 16 in.
SF = 1.25
To find the power capacity, we need to calculate the tension in the belt first. Then we can substitute the values into the power capacity formula.
To find the distance between centers, we can substitute the values into the distance formula.
Note: OCR errors and mathematical errors may be present in the original text.