00:01
For this problem on the topic of relativity, we are told that in high energy physics, new particles can be created by collisions of fast -moving projectile particles.
00:10
Now, some of the kinetic energy of the incident particle can be used to create the mass of the new particle.
00:15
For a proton -proton collision, we can create negative caons and positive caons, as given in the equation, in the reaction equation.
00:25
And we want to find the minimum kinetic energy of the incident proton that will allow this reaction to occur.
00:30
If the second proton is initially at rest.
00:33
We are given the rest energy of each caon to be 493 .7 mega electron volts and the rest energy of a proton to be 938 .3 mega electron volts.
00:43
We want to know then how this calculated minimum kinetic energy compares with the total rest -mats energy for the created caons.
00:51
And then suppose that the two protons are both in motion with velocities of equal magnitude in opposite direction and we want to then find the minimum combined kinetic energy of the two protons that will allow the reaction to occur.
01:05
Now we can apply the conservation of total energy in the frame in which the total momentum is zero, which is the center of momentum frame.
01:12
In the center of momentum frame, the two protons approach each other with equal velocities.
01:17
After the collision, the two protons are at rest, but now they are caons as well.
01:21
In the situation, the kinetic energy of the protons must equal the total rest energy of the two caons.
01:28
And so two times gamma for the center of moment.
01:33
Momentum frame minus 1 into the mass of the proton times c squared must equal to two times the mass of the caons times c squared...