Question

Compare the de Broglie wavelength of a proton moving at $1.30 \times 10^7$ miles per hour ($5.81 \times 10^6$ m/s) to that of a bullet moving at 700 miles per hour (313 m/s) and an electron with a speed of $1.30 \times 10^7$ miles per hour ($5.81 \times 10^6$ m/s). Particle Mass (kg) Velocity (m/s) Wavelength Region proton $1.67 \times 10^{-27}$ $5.81 \times 10^6$ bullet 0.00190 313 electron $9.11 \times 10^{-31}$ $5.81 \times 10^6$

          Compare the de Broglie wavelength of a proton moving at $1.30 \times 10^7$ miles per hour ($5.81 \times 10^6$ m/s) to that of a bullet moving at 700 miles per hour (313 m/s) and an electron with a speed of $1.30 \times 10^7$ miles per hour ($5.81 \times 10^6$ m/s).
Particle Mass (kg) Velocity (m/s) Wavelength Region
proton $1.67 \times 10^{-27}$ $5.81 \times 10^6$
bullet 0.00190 313
electron $9.11 \times 10^{-31}$ $5.81 \times 10^6$

Compare the de Broglie wavelength of a proton moving at 1.30 × 10^7 miles per hour (5.81 × 10^6 m/s) to that of a bullet moving at 700 miles per hour (313 m/s) and an electron with a speed of 1.30 × 10^7 miles per hour (5.81 × 10^6 m/s).
Particle Mass (kg) Velocity (m/s) Wavelength Region
proton 1.67 × 10^-27 5.81 × 10^6
bullet 0.00190 313
electron 9.11 × 10^-31 5.81 × 10^6

Added by Thomas C.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Supreeta N

03/20/2023

Step 1

To convert miles per hour to meters per second, we need to use the conversion factor 1 mile = 1609.34 meters and 1 hour = 3600 seconds. Speed of the proton in meters per second = (1.30 x 10^7 miles/hour) * (1609.34 meters/mile) * (1 hour/3600 seconds) Show more…

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Texts: with a speed of 1.30x10^7 miles per hour (5.81x10^6 m/s). Particle Mass (kg) Velocity (m/s) Wavelength Region proton 1.67 x 10^-27 5.81 x 10^6 bullet 0.00190 313 electron 9.11 x 10^-31 5.81 x 10^6