Question

Write each vector as a linear combination of the vectors in S. (Use $s_1$ and $s_2$, respectively, for the vectors in the set. If not possible, enter IMPOSSIBLE.) S = {(1, 2, -2), (2, -1, 1)} (a) z = (-12, 1, -1) z = (b) v = (-1, -6, 6) v = (c) w = (-4, -18, 18) w = (d) u = (1, -6, -6) u =

          Write each vector as a linear combination of the vectors in S. (Use $s_1$ and $s_2$, respectively, for the vectors in the set. If not possible, enter IMPOSSIBLE.)
S = {(1, 2, -2), (2, -1, 1)}
(a) z = (-12, 1, -1)
z =
(b) v = (-1, -6, 6)
v =
(c) w = (-4, -18, 18)
w =
(d) u = (1, -6, -6)
u =

Write each vector as a linear combination of the vectors in S. (Use s1 and s2, respectively, for the vectors in the set. If not possible, enter IMPOSSIBLE.)
S = (1, 2, -2), (2, -1, 1)
(a) z = (-12, 1, -1)
z =
(b) v = (-1, -6, 6)
v =
(c) w = (-4, -18, 18)
w =
(d) u = (1, -6, -6)
u =

Added by Jaime J.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Yuva S

12/20/2021

Step 1

(a) z = (12, 1, -1) To write z as a linear combination of the vectors in S, we need to find scalars x1, x2, x3, x4, x5, and x6 such that: z = x1(1) + x2(2) + x3(-2) + x4(2) + x5(-1) + x6(1) Simplifying the equation, we get: (12, 1, -1) = x1(1, 0, 0) + x2(0, 2, Show more…

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Texts: Write each vector as a linear combination of the vectors in S. (Use S1 and S2, respectively, for the vectors in the set. If not possible, enter IMPOSSIBLE.) S = {1, 2, -2, 2, -1, 1} (a) z = (12, 1, -1) (b) v = (-1, -6, 6) (c) w = (-4, -18, 18) (d) u = (1, -6, -6) Need Help? RoadI Waoeh lt