00:01
All right, so for this problem, we have a system of two exponentials, and we're going to solve the system.
00:08
We can do either elimination or substitution.
00:11
Both will work.
00:12
But if we examine this, we can tell that y is already solved for in the second equation.
00:18
So it'd be quite convenient to just substitute it into the first equation.
00:22
So let's do that to start.
00:24
So if we do that, we will get 9 to the power of x plus 2 minus 3 to the 1.
00:32
The x squared plus 2x power equals 0.
00:38
And what we can do here is we can actually rewrite this first term because 9 is a power of 3.
00:44
So we can write this as 3 squared to the x plus 2.
00:51
And the reason why we want to do that is that if they have the same base, we can go a lot further with operations on these terms.
01:00
And so we can also simplify this again to 3.
01:04
To the 2 parentheses x plus 2 using our exponent rules.
01:14
So now that they have the same base, let's go ahead and add this second term over to the other side.
01:20
So we get 3 to the 2 parentheses x plus 2 power equals 3 to the x squared plus 2x power.
01:31
Since they have the same base, we can really simply bring down the exponents.
01:36
We just have to log base 3 both sides.
01:38
So if we do that, we get the exponents are equaling each other.
01:42
We get two, parentheses, x plus two, equals x squared plus 2x.
01:51
And now this is just a quadratic.
01:54
So let's go ahead and distribute this expression...