You may need to use the appropriate technology to answer this question. The following data are from a completely randomized design. Treatmam Tesztmart A B C 33 43 33 29 44 36 29 44 35 27 46 36 32 48 40 Bemple mac 30 45 36 Sampla vertence 6:00 4.00 6.50 (a) At the $\alpha = 0.05$ level of significance, can we reject the null hypothesis that the means of the three treatments are equal? (b) Use Fisher's LSD procedure to test whether there is a significant difference between the means for treatments A and B, treatments A and C, anc (c) Use Fisher's LSD procedure to develop a 95% confidence interval estimate of the difference between the means of treatments A and B
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Treatment A: Mean = (43 + 44 + 46 + 48 + 49 + 33 + 36 + 35 + 36 + 40 + 29 + 29 + 27 + 32 + 30 + 36) / 16 = 36.625 Standard Deviation = sqrt(((43-36.625)^2 + (44-36.625)^2 + (46-36.625)^2 + (48-36.625)^2 + (49-36.625)^2 + (33-36.625)^2 + (36-36.625)^2 + Show moreā¦
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Problem #7: Using the data from Problem #6 above, apply Fisher's LSD method to determine the following at a 1% significance level: are the means of the three hypotheses significantly different? State the critical value of LSD, the number of hypotheses that are significantly different, and which pairs are significantly different (using Fisher's LSD test at the 1% significance level). Hypotheses: H0: Āµ1 = Āµ2 = Āµ3 Ha: At least one mean is different Critical value of LSD: 1.90 Number of significantly different hypotheses: 2 Pairs that are significantly different: (B) - (F) and (G) - all of them Problem #7a) Which hypothesis is true? Justify your answer. Answer: 7a) Hypothesis 2 is true.
Adi S.
The following data are from a completely randomized design. $$\begin{array}{lccc} & \text { Treatment } & \text { Treatment } & \text { Treatment } \\& \text { A } & \text { B } & \text { C } \\& & & \\& 32 & 44 & 33 \\& 30 & 43 & 36 \\& 30 & 44 & 35 \\& 26 & 46 & 36 \\& 32 & 48 & 40 \\ \text { Sample mean } & 30 & 45 & 36 \\\text { Sample variance } & 6.00 & 4.00 & 6.50\end{array}$$ a. At the $\alpha=.05$ level of significance, can we reject the null hypothesis that the means of the three treatments are equal? b. Use Fisher's LSD procedure to test whether there is a significant difference between the means for treatments $\mathrm{A}$ and $\mathrm{B},$ treatments $\mathrm{A}$ and $\mathrm{C},$ and treatments $\mathrm{B}$ and $\mathrm{C} .$ Use $\alpha=.05$ c. Use Fisher's LSD procedure to develop a $95 \%$ confidence interval estimate of the difference between the means of treatments $A$ and $B$.
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