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Hello everyone.
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So in this question we have given, the vashler adult intelligence scale, w -ais, is the most common iq test.
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Main score is 100 and standard deviation is 15.
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Now we have to find percent of people have w -a -i -s scores above 70 and percent of people have w -a -is scores below 145.
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So now here we have given that mu is equal to 100, which is mean, and standard deviation, that is sigma is equal to 15.
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So first of all, we will find percent of people have w ais score above 17.
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So now let us take x is equal to wais scores.
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So first of all, we have to find the percent of people have wai scores above 70.
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So in order to find this, first of all, we have to find z score and z score is equal to x minus mu divided by sigma.
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So here, x is 70 minus mu is 100 divided by sigma is 15.
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So on solving this, we will get minus 2.
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So this is our z score.
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And here we have to use 68, 95, 99 .7 rule.
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Now let us understand this rule...