00:01
Students welcome here in this question we have some compounds so a ethanol is given ethanol and b is di chloromethane and c bromomethine and d is acetone so they are asking here in c is the signal so we have to say if you see in proton this one is ch3 ch2 oh okay there is a triplet for quadrate for this carbon and there is a triplet for this carbon so there is no singlets in this one so it is wrong dichloromethane so dichloromethane means ch3 cl is given.
01:09
So there is no two signals, ch2, cl2.
01:13
So there are no two signals for c -13 n -mr.
01:18
So it is wrong.
01:19
Bromomethen, ch3, br, it is having only one signal for c -13 n -mr.
01:29
And acetone, if you see c -1 -o, ch3 and ch3.
01:34
So in c13 nmr, it is carbonyl carbon.
01:39
For this carbon, it is having 205 ppm.
01:45
And for methyl stretch, there is 30 ppm is present.
01:50
So 2 are there...