Question

The 2nd order rate constant for the decomposition of a certain substance is 1.70 x 10^-2 L mol^-1 s^-1 at 30°C and 2.01 L mol^-1 s^-1 at 37°C. Determine the activation energy and the pre-exponential factor.

          The 2nd order rate constant for the decomposition of a certain substance is 1.70 x 10^-2 L mol^-1 s^-1 at 30°C and 2.01 L mol^-1 s^-1 at 37°C. Determine the activation energy and the pre-exponential factor.
        

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Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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The 2nd order rate constant for the decomposition of a certain substance is 1.70 x 10^-2 L mol^-1 s^-1 at 30°C and 2.01 L mol^-1 s^-1 at 37°C. Determine the activation energy and the pre-exponential factor.
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Transcript

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00:01 Question is the second order rate constant for the decomposition of a certain substance is this at this temperature this is the concentration at the 37th century date calculate the activation energy and pre exponential factor so what we can do log k2 by k1 equal to ea divided by 2 .303 r 1 by t 1 by t 1 minus 1 by 2 2 2 2 it is the expression.
00:40 Now we will put the values log k2 by k1.
00:45 K2 second rate constant is given 2 .01 divided by rate constant 1 .7 devoured it is.
00:58 Ea we have to calculate divided by 2 .303 multiply 8 .311 by t1 initial temperature that is given 30 degrees centigrade.
01:10 Means it will be equal to 303 kelvin, 303 kelvin minus 1 by t2.
01:20 T2 is given 37 .8 centredate.
01:26 310 kelvin.
01:28 Right.
01:29 So what is the value of the activation energy? that will be equal to 2 .13 multiplied 10 raised to the power 3...
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