00:01
First of all, you want to write down the reaction, glucose plus atp.
00:14
And the enzyme is hexokinase and you turn them into glucose 6 -phosphate g6p and release adp.
00:25
Now according to this reaction, the delta g0 reaction is delta g atp hydrolysis, minus delta g of g of g6p hydrodot 6.
00:47
Now we know that delta g of 80p is negative 7700, then the delta g of g6p is negative 3 ,138.
01:07
So then you get actually negative negative 4 ,562 p.
01:20
Per mole.
01:23
Next step, you want to calculate the k -eq.
01:26
So we know that the relationship is delta g 0 equals negative rt, multiplied by the natural log of k .eq.
01:37
And we wanna find out k -eq, so we have to rearrange it.
01:41
K -eq equals the base of e and then the power is negative delta g 0 divided by r t and we know that r is the ideal gas constant 8 .314 joule per mole k t is the temperature at 25 degrees celsius so it's 23073 k plus 25 degrees celsius which is 298 so let's plug in all the value.
02:21
We know that delta g 0 is negative 4 ,562, divided by 8 .314 times 298...