Question

The 550 g bar is rotating as shown in (Figure 1). 2.0 m 120 rpm Part A What is the magnitude of the angular momentum of the bar? |L| = kg m²/s Part B What is the direction of the angular momentum of the bar? into the page out of the page Correct

          The 550 g bar is rotating as shown in (Figure 1).
2.0 m
120 rpm
Part A
What is the magnitude of the angular momentum of the bar?
|L| = kg m²/s
Part B
What is the direction of the angular momentum of the bar?
into the page
out of the page
Correct

The 550 g bar is rotating as shown in (Figure 1).
2.0 m
120 rpm
Part A
What is the magnitude of the angular momentum of the bar?
|L| = kg m²/s
Part B
What is the direction of the angular momentum of the bar?
into the page
out of the page
Correct

Added by Beatriz C.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Ashar Tanveer

07/22/2023

Step 1

We can do this by using the formula: ω = Δθ/Δt where ω is the angular velocity, Δθ is the change in angle, and Δt is the time taken for the change. From the figure, we can see that the bar rotates through an angle of 120 degrees in 2 seconds. Therefore, ω = Show more…

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The 550 g bar is rotating as shown in (Figure 1). Part A What is the magnitude of the angular momentum of the bar? Answer in kg m²/s Part B What is the direction of the angular momentum of the bar? into the page out of the page