The absolute magnitude of a star in the Andromeda galaxy (distance 690 kpc) is M = 5. It explodes as a supernova, becoming one billion (10^9) times brighter. What is its apparent magnitude?
Added by Kayla P.
Step 1
This relationship is given by the distance modulus formula: m = M + 5 log10(d) - 5 where d is the distance in parsecs. Given that the distance to the Andromeda galaxy is 690 kpc, we need to convert this to parsecs. 1 kpc = 1000 parsecs, so 690 kpc = 690,000 Show more…
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