The acceleration of a particle is given by
ax(t) = -2.08 m/s^2 + (3.03 m/s^3)t. Find the initial velocity v0x such
that the particle will have the same x-coordinate at time t =
4.01 s as it had at t = 0. Express your answer in meters per
second.
Part B: What will be the velocity at time t = 4.01 s?
Express your answer in meters per second.