00:01
In this question, the given data is between x and px of x, that is the probability mass function of x between the given values.
00:10
Here, let us assume, x be the rated capacity of a freezer of a freezer of this brand sold at a certain store in hadry.
00:26
Now, computing the expected value of x, denoted by e of x, will be equal to x 1 times.
00:34
X1 plus x2 times p of x2 plus x3 times p of x3 which is equal to 16 times p of 16 plus 18 p of 18 plus 20 times p of 20 on substituting the values from the given data we get 16 times of 0 .2 plus 18 times of 0 .5 plus 20 times of 0 .5 plus 20 times of 0 .3.
01:05
And calculating this, we get the expected value e of x is equal to 18 .2.
01:11
Therefore, the expected capacity of a freezer of a brand is 18 .2.
01:18
Now next, computing the value of e of x squared is equal to x1 square of p of x2 plus x2 square times of p of x2 plus x3 square times p of x3 and so on till xn square times p of xin.
01:39
On computing the values were, we get 16 square times p of 16 plus 18 square times p of 18 plus 20 square times p of 20.
01:51
On substituting the values here, we get the final solution of e of x squared.
01:57
Be equal to 33 .2.
02:01
Therefore, the expected value of x square is 33 .3 .2.
02:09
Now, the variance can be computed as variance denoted by v of x is equal to e of x squared minus e of x whole square.
02:21
This is equal to 333 .2 minus 18 .2 both square...