Question

The activation energy for the gas phase decomposition of vinyl ethyl ether is 183 kJ. $CH_2=CH-OC_2H_5 \rightarrow C_2H_4 + CH_3CHO$ The rate constant at 647 K is $4.46 \times 10^{-4} s^{-1}$. The rate constant will be $0.00343 s^{-1}$ at __ K.

          The activation energy for the gas phase decomposition of vinyl ethyl ether is 183 kJ.
$CH_2=CH-OC_2H_5 \rightarrow C_2H_4 + CH_3CHO$
The rate constant at 647 K is $4.46 \times 10^{-4} s^{-1}$. The rate constant will be $0.00343 s^{-1}$ at __ K.

The activation energy for the gas phase decomposition of vinyl ethyl ether is 183 kJ.
CH2=CH-OC2H5 → C2H4 + CH3CHO
The rate constant at 647 K is 4.46 × 10^-4 s^-1. The rate constant will be 0.00343 s^-1 at K.

Added by Sarah S.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

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The activation energy for the gas phase decomposition of vinyl ethyl ether is 183kJ. CH_(2)=CH-OC_(2)H_(5)->C_(2)H_(4)+CH_(3)CHO The rate constant at 647K is 4.46 imes 10^(-4)s^(-1). The rate constant will be 0.00343s^(-1) at The activation energy for the gas phase decomposition of vinyl ethyl ether is 183 kJ CH=CH-OCH5-CH+CHCHO K.