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The admissions officer at a small college compares the scores on the Scholastic Aptitude Test (SAT) for the school's in-state and out-of-state applicants. A random sample of 9 in-state applicants results in a SAT scoring mean of 1165 with a standard deviation of 44. A random sample of 13 out-of-state applicants results in a SAT scoring mean of 1220 with a standard deviation of 55. Using this data, find the 98% confidence interval for the true mean difference between the scoring mean for in-state applicants and out-of-state applicants. Assume that the population variances are not equal and that the two populations are normally distributed. Step 1 of 3: Find the point estimate that should be used in constructing the confidence interval. Step 2 of 3: Find the margin of error to be used in constructing the confidence interval. Round your answer to six decimal places Step 3 of 3: Construct the 98% confidence interval. Round your answers to the nearest whole number.

          The admissions officer at a small college compares the scores on
the Scholastic Aptitude Test (SAT) for the school's in-state and
out-of-state applicants. A random sample of 9 in-state
applicants results in a SAT scoring mean of 1165 with a
standard deviation of 44. A random sample
of 13 out-of-state applicants results in a SAT scoring
mean of 1220 with a standard deviation of 55. Using
this data, find the 98% confidence interval for the true
mean difference between the scoring mean for in-state applicants
and out-of-state applicants. Assume that the population variances
are not equal and that the two populations are normally
distributed.
Step 1 of 3: 
Find the point estimate that should be used in constructing the
confidence interval.
Step 2 of 3: 
Find the margin of error to be used in constructing the
confidence interval. Round your answer to six decimal places
Step 3 of 3: 
Construct the 98% confidence interval. Round your
answers to the nearest whole number.
        
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Added by Scott M.

Elementary Statistics a Step by Step Approach
Elementary Statistics a Step by Step Approach
Allan G. Bluman 9th Edition
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The admissions officer at a small college compares the scores on the Scholastic Aptitude Test (SAT) for the school's in-state and out-of-state applicants. A random sample of 9 in-state applicants results in a SAT scoring mean of 1165 with a standard deviation of 44. A random sample of 13 out-of-state applicants results in a SAT scoring mean of 1220 with a standard deviation of 55. Using this data, find the 98% confidence interval for the true mean difference between the scoring mean for in-state applicants and out-of-state applicants. Assume that the population variances are not equal and that the two populations are normally distributed. Step 1 of 3: Find the point estimate that should be used in constructing the confidence interval. Step 2 of 3: Find the margin of error to be used in constructing the confidence interval. Round your answer to six decimal places Step 3 of 3: Construct the 98% confidence interval. Round your answers to the nearest whole number.
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Transcript

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00:01 Hello students, let's do this question.
00:02 In this question, sample size n1 equals 13, n2 equal to 9, then xbore equal to 1 ,220, y bai equal to 1 ,165, then sigma 1 equal to 55 and sigma 2 equal to 44.
00:22 Is given and we have to find out 98 % confidence interval for difference between domains that is mu1 minus mu 2.
00:32 Now the formula for confidence interval equal to ci equal to x bar minus y bar plus minus z of 5 2 into square root of sigma 1 square upon n1 plus sigma 2 square 1st2 and here the margin of error equal to margin of error of error equal to z alpha by 2 into square root of sigma 1 square upon n 1 plus sigma 2 square upon n 2 now put the balance then we get confidence interval c i equal to x bar minus y bar that is 1 ,220 minus 1 ,165 plus minus value of z at 98 % is 2 .36 into square root of sigma 1 square upon n1, that is 55 square upon 13 plus 44 square divided by 9 equals to 55 plus 25 plus minus 50 .2757 equal to 4 .7 to to 100n .2757...
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