00:01
Consider sub part a.
00:03
The equation for the wavelength of the sound, if the police curve was a trust is given by lambda is equal to v by f.
00:13
Here, v is the speed of the sound in air and f is the frequency of the sound.
00:19
Substituting the values in the equation gives, lambda is equal to 343 meter per second divided by 1000 heads which is equal to 0.
00:30
0 .343 meter.
00:33
Therefore the answer to subpart a is equal to 0 .343 meter.
00:40
Now consider subpart b.
00:42
The equation for the frequency of sound in front of the polyscar is given by f prime is equal to f into v by v minus vs.
00:54
Here vs is the speed of the polyscar.
00:57
The equation for the wavelength of the sound is in front of the holy scar is given by lambda prime is equal to v by f prime.
01:07
Substituting the expression for f prime gives lambda prime is equal to v by f into v by v minus vs or lambda prime is equal to v by f into v minus vs by v or lambda prime is equal to v by f by f, substituting the values in the equation gives, lambda prime is equal to 343 meter per second minus 40 meter per second divided by 1000 heads which is equal to 0 .303 meter...