00:01
Hello, for the first part of this question, the amplitude of a standing wave in a closed pipe is illustrated.
00:06
In a closed pipe, only odd harmonics are present in the standing wave.
00:16
In the fundamental or first harmonic mode of vibration, only one node is present in the standing wave formed in a closed pipe.
00:27
In the third harmonic mode of vibration, two nodes are present in the standing wave.
00:32
And in the fifth harmonic mode of vibration, three notes are present in the standing wave.
00:40
In the given standing wave, we can see that three nodes are present.
00:44
Therefore, the harmonic number for the mode of oscillation is 5.
00:55
Now let's solve the second part of this question.
00:59
The frequency of sound in a closed pipe can be given by f is equal to nv divided by 4l.
01:08
Here n represents the number of harmonics and n can take only out number of values.
01:14
V is the speed of sound in air and l is the length of the closed pipe.
01:19
Now let's substitute the values.
01:21
So it equals n is obtained as 5 from part 1, 5 into...