The angular position of a point on a rotating wheel is given by θ = 1 + 8t^2 +5t^3, where θ is in radians and t is in seconds. (a) What is its angular velocity at t = 3 s? (b) Calculate its angular acceleration at t = 6 s.
Added by Debbie H.
Step 1
Step 1: Find the angular velocity at t = 3 s** Given: θ = 1 + 8t^2 + 5t^3 Angular velocity, ω = dθ/dt Taking the derivative of θ with respect to t: ω = 16t + 15t^2 Plugging in t = 3 s: ω = 16(3) + 15(3)^2 ω = 48 + 135 ω = 183 rad/s ** Show more…
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