The energy released by each fission within the core of a nuclear reactor is 2.00 \times 10^2 MeV. The number of fissions occurring each second is 4.20 \times 10^{17}. Determine the power (in watts) that the reactor generates.
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1 MeV = 1.6 x 10^-13 Joules So, 2.00 x 10^2 MeV = 2.00 x 10^2 x 1.6 x 10^-13 Joules = 3.20 x 10^-11 Joules Show more…
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