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The answer to part (d) could also have been obtained from the electric field derived for a parallel plate capacitor E = σ/ε0. QUESTION: How do the following change if the distance between the plates is doubled? (Select all that apply.) The capacitance is halved. The electric field between the plates is halved. The charge is doubled. The electric field between the plates remains the same. The charge is halved. The capacitance is doubled. Use the worked example above to help you solve this problem. A parallel-plate capacitor has an area A = 2.30 x 10^-4 m^2 and a plate separation d = 1.10 x 10^-3 m. (a) Find its capacitance. [F] (b) How much charge is on the positive plate if the capacitor is connected to a 3.00 V battery? [C] (c) Calculate the charge density on the positive plate, assuming the density is uniform. [C/m^2] (d) Calculate the magnitude of the electric field between the plates. [V/m] Two plates, each of area 3.30 x 10^-4 m^2, are used to construct a parallel-plate capacitor with capacitance 1.00 pF. (a) Find the necessary separation distance. [d] (b) If the positive plate is to hold a charge of 5.00 x 10^-12 C, find the charge density. [σ] (c) Find the electric field between the plates. [E] (d) What voltage battery should be attached to the plate to obtain the preceding results? [V]

          The answer to part (d) could also have been obtained from the electric field derived for a parallel plate capacitor E = σ/ε0.

QUESTION: How do the following change if the distance between the plates is doubled? (Select all that apply.)

The capacitance is halved.
The electric field between the plates is halved.
The charge is doubled.
The electric field between the plates remains the same.
The charge is halved.
The capacitance is doubled.

Use the worked example above to help you solve this problem. A parallel-plate capacitor has an area A = 2.30 x 10^-4 m^2 and a plate separation d = 1.10 x 10^-3 m.

(a) Find its capacitance. [F]
(b) How much charge is on the positive plate if the capacitor is connected to a 3.00 V battery? [C]
(c) Calculate the charge density on the positive plate, assuming the density is uniform. [C/m^2]
(d) Calculate the magnitude of the electric field between the plates. [V/m]

Two plates, each of area 3.30 x 10^-4 m^2, are used to construct a parallel-plate capacitor with capacitance 1.00 pF.

(a) Find the necessary separation distance. [d]
(b) If the positive plate is to hold a charge of 5.00 x 10^-12 C, find the charge density. [σ]
(c) Find the electric field between the plates. [E]
(d) What voltage battery should be attached to the plate to obtain the preceding results? [V]

Added by Arthur G.

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