00:01
Okay, so i have in number three, the length of the arc, and arc length is equal to theta times the radius.
00:12
So theta is arc length over radius.
00:17
So in this problem, theta is arc length is four over radius six, so that's two -thirds radiance.
00:29
I'm getting that because i want to find the area of the sector.
00:34
Area of a sector is half r squared theta.
00:39
So that's half six squared times two thirds.
00:45
So 36 divided by 2 is 18.
00:52
So this is 18 times 2 thirds.
00:56
So that is 12 centimeters.
01:00
Meters squared for that area.
01:05
Okay, so that takes care of number three.
01:10
Now to move on to number four, which is a little confusing because it uses similar letters here.
01:19
Okay, so we have a, b, this is r, these are lowercase r's and that's o.
01:29
Okay, so we have a sector, a, o b, the radius is r, the area of the sector is 15 centimeters squared, and angle aob is 1 .5 radiance.
01:51
Okay, so i want to show that the radius is 2 -r -5.
01:56
Okay, so area again is half r squared theta.
02:03
So 15 equals half r squared and the measure of theta is 1 .5.
02:16
I'm going to multiply both sides by 2.
02:20
So i have 30 equals r squared times 1 .5.
02:29
If i divide both sides by 1 .5, i get r squared is 20, so r is the square root of 20, which is 2 radical 5.
02:50
So that takes care of part a.
02:55
Now let's see b, i want to find the perimeter of the sector.
03:02
Okay, so to find the perimeter of the sector, i need the two sides, right? let me just draw that...