Question

The average waiting time to be seated for dinner at a popular restaurant is 23.5 minutes, with a standard deviation of 3.6 minutes. Assume the variable is normally distributed. When a customer arrives at the restaurant for dinner, find the probability that the customer will have to wait the following time Between 16 and 22 minutes. Less than 19 minutes or more than 25 minutes Less than 15 minutes

Name: the average waiting time to be seated for dinner at a popular restaurant is 235 minutes with a standard deviation of 36 minutes assume the variable is normally distributed when a customer ar 95665
Uploaded: 2023-08-19T01:38:20-08:00
Duration: 1 min 5 s
Channel: Prabhakar Kumar
Description: the average waiting time to be seated for dinner at a popular restaurant is 235 minutes with a standard deviation of 36 minutes assume the variable is normally distributed when a customer ar 95665

          The average waiting time to be seated for dinner at a popular
restaurant is 23.5 minutes, with a standard deviation of 3.6
minutes.  Assume the variable is normally distributed. 
When a customer arrives at the restaurant for dinner, find the
probability that the customer will have to wait the following
time
Between 16 and 22 minutes.
Less than 19 minutes or more than 25 minutes
Less than 15 minutes

Added by Joshua M.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Prabhakar Kumar

08/19/2023

Step 1

The z-score formula is: $z = \frac{x - \mu}{\sigma}$ where $x$ is the time value, $\mu$ is the mean, and $\sigma$ is the standard deviation. Show more…

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The average waiting time to be seated for dinner at a popular restaurant is 23.5 minutes, with a standard deviation of 3.6 minutes. Assume the variable is normally distributed. When a customer arrives at the restaurant for dinner, find the probability that the customer will have to wait the following time Between 16 and 22 minutes. Less than 19 minutes or more than 25 minutes Less than 15 minutes