The battery of an electric car holds 75.55 MJ of energy. How many supercapacitors with C = 4.169 kF rated for 2.351 V would be required to supply this amount of energy?
Added by Sue W.
Step 1
Given: - \(C = 4.169 \, \text{kF} = 4.169 \times 10^3 \, \text{F}\) - \(V = 2.351 \, \text{V}\) Substituting the values: \[ E = \frac{1}{2} \times (4.169 \times 10^3) \times (2.351)^2 \] Show more…
Show all steps
Your feedback will help us improve your experience
Shahab Ullah and 87 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The battery of an electric car stores $53.63 \mathrm{MJ}$ of energy. How many supercapacitors, each with capacitance $C=3.361 \mathrm{kF}$ at a potential difference of $2.121 \mathrm{~V},$ are required to supply this amount of energy?
The battery of an electric car stores 60.51 MJ of energy. If 6990 supercapacitors, each with capacitance $C=3.423 \mathrm{kF}$, are required to supply this amount of energy, what is the potential difference across each supercapacitor?
The battery of an electric car stores 67.39 MJ of energy. If 6845 supercapacitors, each with capacitance $C$ and charged to a potential difference of $2.377 \mathrm{~V}$, can supply this amount of energy, what is the value of $C$ for each supercapacitor?
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD