00:01
Hi, so we have two questions here.
00:07
So for the first one, we are to identify the element that produces yttrium -90.
00:14
So we have a beta decay.
00:16
Okay, so let's write here what will be our reactant here if the reaction produces, erase this first, if the reaction produces a beta particle.
00:33
Now remember that a beta particle could have a symbol of this one or electron.
00:40
Okay, it has a relative mass of zero and then it has negative one charge.
00:46
Okay, so this is right here, beta particles.
00:53
Okay, so if we have an element that undergoes beta decay, that means it emits a beta particle.
01:01
So we could write or we could just use the one with the electron symbol e and then mass zero, negative one charge, and it produces the element yttrium -90.
01:13
So it has a mass of 90 and then symbol for yttrium is y and what's the atomic number of yttrium? we'll get that from the predict table that's going to be 39.
01:25
So what we'll do here is we will balance the numbers on the upper left and on the lower left on both sides of the equation.
01:33
So we'll just add 90 plus zero, of course it's 90, and then 39 plus negative one, this will give us 38.
01:42
So our equation will look like this.
01:45
We have an element which has a mass of 90, an atomic number of 38, and take the predict table and see which element has an atomic number of 38 and that's going to be strontium, sr.
01:59
Okay, so our balance equation for this will be zero, negative one, electron plus 90, 39, yttrium...