Question

The block diagram for a process with feedback control for output deviation variable h is shown in the figure below. All transfer functions are given with pre-factor of s in minutes. A unit change is made in the set-point at t = 0. The time required for h to reach 50% of its ultimate value, in minutes (up to two decimal places), is ________ Gc(s) = 0.5s Gf(s) = 0.2 / (1.5s + 1) Gp(s) = 1 / 0.5s Gm(s) = 1 Gd(s) = 1 / 0.5s

          The block diagram for a process with feedback control for output deviation variable h is shown in the figure below. All transfer functions are given with pre-factor of s in minutes. A unit change is made in the set-point at t = 0. The time required for h to reach 50% of its ultimate value, in minutes (up to two decimal places), is ________
Gc(s) = 0.5s
Gf(s) = 0.2 / (1.5s + 1)
Gp(s) = 1 / 0.5s
Gm(s) = 1
Gd(s) = 1 / 0.5s

The block diagram for a process with feedback control for output deviation variable h is shown in the figure below. All transfer functions are given with pre-factor of s in minutes. A unit change is made in the set-point at t = 0. The time required for h to reach 50% of its ultimate value, in minutes (up to two decimal places), is
Gc(s) = 0.5s
Gf(s) = 0.2 / (1.5s + 1)
Gp(s) = 1 / 0.5s
Gm(s) = 1
Gd(s) = 1 / 0.5s

Added by Joan T.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Kratika Bhadauria

01/31/2024

Step 1

We can do this by multiplying the transfer functions of each block in the feedback loop. Show more…

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The block diagram for a process with feedback control for output deviation variable h is shown in the figure below.All transfer functions are given with pre-factor of s in minutes.A u change is made in the set-point at t=0.The time required for h to reach 50% of its ultimate value,in minutes (up to two decimal places),is