00:01
Hello, it is given that the mass of the block m, m here is 0 .5 kgggs, and the density of the block row here, that is equal to 2 .7, multiply 10 to the power 3 kg per meter cube.
00:13
This is kg per meter cube.
00:15
And when submerged in water, the free body diagram for the block is as follows.
00:18
So let us consider this is the surface of water and this is a block which is submerged inside the water.
00:23
There is a tension to acting upwards.
00:24
There is a mass of block acting downward and there is what we can say the buoy force which is acting in the upward direction.
00:30
So from here we can write from newton's equation of motion t plus f v that is equal to m g that is summation of the force acting on the block equal to zero.
00:40
The total force acting on the block equal to zero because the block is an equilibrium.
00:43
So two plus f b equal to m g.
00:44
This implies that t equals m g minus f b that is the point force and the point force in this case is equal to v row wg and row here is in this case is the density of water...