00:01
Hello everyone, we are going to understand this question.
00:05
Here, given in the question, given, mass of block, m is equal to 10 kilogram, applied force f is equal to 10 newton, and angle theta is equal to 37 degrees.
00:33
Here, mass of the block, his weight of the block is working vertically downward, that is, m into g.
00:43
Applied force is at angle 37.
00:50
So vertical component of force is f -sign 37 and horizontal component of force is f -cost 37.
01:02
And there is a friction force along to ground because it is applying forces in right side, so friction force will be in left side.
01:13
And normal reaction due to the weight of the object, that is, which is vertically upward direction.
01:21
Now we can write, we can apply the force balance equation in vertical direction, force balance in vertical direction.
01:42
So we can write n plus f -sign 37 is equal to m into g.
01:53
Now we can write n is equal to m g minus f -sign 37 f -sign 37 now substituting the value in this here value of mass that is given 10 kg value of gravitational acceleration that is 10 and value of f is given 10 10 newton into sine 37 that is 3 upon 5 now doing the further calculation so we will get 100 minus 6 newton.
02:33
After doing the further calculation, we will get 94 newton...