The body weight (i.e. gravitational force) and forces from the ground on the heel and balls of the feet cause a ____ load in the foot.
Added by Margaret A.
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Step 1: Identify the forces acting on the foot – body weight (gravity) acting downward and ground reaction forces acting upward through the heel and forefoot. Show more…
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A person who weighs 751 N supports himself on the ball of one foot. The normal force N = 751 N pushes up on the ball of the foot on one side of the ankle joint, while the Achilles tendon pulls up on the foot on the other side of the joint. The center of gravity of the person is located right above the tibia. Gastrocnemius-soleus muscles Achilles tendon Tibia Calcaneus (heel bone) 12.8 cm 4.60 cm
Sri K.
A woman might wear a pair of flat shoes to work during the day, as in Figure $11-43$ (a). but a pair of high heels, Figure $11-43$ (b). when going out for the evening. Assume that each foot supports half her weight, $w=W / 2=279 \mathrm{N},$ and that the forces exerted by the floor on her feet occur at the points $A$ and $B$ in both figures. Find the forces $F_{A}($ point $A)$ and $F_{B}($ point $B)$ for $(a)$ flat shoes and $(b)$ high heels. (c) How have the high heels changed the weight distribution between the woman's heels and toes?
Flats Versus Heels A woman might wear a pair of flat shoes to work during the day, as in FlGuRE $11-61$ (a), but a pair of high heels, FIGURE $11-61(\mathrm{b}),$ when going out for the evening. Assume that each foot supports half her weight, $w=W / 2=279 \mathrm{N},$ and that the forces exerted by the floor on her feet occur at the points A and B in both figures. Find the forces $F_{A}($ point $A)$ and $F_{B}$ (point B) for (a) flat shoes and (b) high heels. (c) How have the high heels changed the weight distribution between the woman's heels and toes?
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