00:01
Hello everybody here in this sum we have to find out a reference diagram.
00:08
Now the racing car started from point o we assume that he started from o and went to the north direction till a and the distance it covered is 4 .47 kilometers.
00:33
Now it took a sharp turn and when in south is south -west direction means this direction here 2 .49 kilometer in this direction and reached point b then again it went straight to another point d towards east direction now from the given data we see that oa is equal to 4 .47 kilometers ab is 2 .49 kilometers and bd is 3 .59 kilometers.
01:24
We need to find out the position of d or distance of d from o means we need to find out o d so o d is how much we need to find out let's see this point is c from triangle acb we say that sign angle cab is equal to 45 degree.
02:01
So sign angle cab will be equal to perpendicular by hypotenuse.
02:10
Now here the perpendicular is bc and the hypotenuse is the hypotenuse is and the hypotenius is a b so if we put the value of a .b that is 2 .49 we will get bc 2 .49 so we get bc as 2 .49 into 545 degree so 2 .49 into root over of 2, 1 by root over of 2 and it will be 1 .76 kilometer.
02:53
So we found bc.
02:56
Next dc is equal to bd minus bc so it will be 3 .59 minus 1 .76 and it will become 1 .83 kilometer.
03:16
Next, this is from triangle a, c we get bc by ac is equal to tan of angle c ab now cab is 45 degree so tan of 45 degree from here we get ac as bc divide by tan 45 degree and that will be 1 .76 so, oc will be equal to oa minus ac that is 4 .47 minus 1 .76 that is equal to 2 .71 kilometer.
04:17
In right angle c...