00:01
Okay, for this question we have to find the downward deflection at point c and b, or delta c and delta b.
00:11
So we have the moment at point c and the excerpt at point b.
00:20
So first we can calculate, we can start with at point c to find the deflection at point c.
00:27
First we consider the moment m0 and we have that the displacement is equal to minus m0 x squared over 2 ei and displacement here is the del we call it del c1 that's the deflection at point c due to the moment and x is equal to l over 2 at point c so that we get del c1, or that is minus mcel, l square over 8, ei.
01:11
Next we find the deflection at c due to the load p, which we have that.
01:18
The deflection is px square over 6ei, time 3l minus x, and x is l over 2, and the deflection is del c2.
01:30
So we have del c2 equal to this 1.
01:34
All we get that it is 5 p .l to the power of 3 divided by 4 8 ei...