Question

the capacitor c1 = 5.41 uF and c2=4 uF are connected in series. after some time, the engineer decided to connect capacitor C3 = 1.81 uF across C1 and C2. find the total charge, in uC, of the group of capacitors if they are connected across 4.87 V battery

Name: the capacitor c1 541 uf and c24 uf are connected in series after some time the engineer decided to connect capacitor c3 181 uf across c1 and c2 find the total charge in uc of the group of ca 06542
Uploaded: 2022-05-14T05:45:24-08:00
Duration: 3 min 13 s
Channel: Mark J
Description: the capacitor c1 541 uf and c24 uf are connected in series after some time the engineer decided to connect capacitor c3 181 uf across c1 and c2 find the total charge in uc of the group of ca 06542

          the capacitor c1 = 5.41 uF and c2=4 uF are connected in series. after some time, the engineer decided to connect capacitor C3 = 1.81 uF across C1 and C2. find the total charge, in uC, of the group of capacitors if they are connected across 4.87 V battery

Added by Richard M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Mark J

05/14/2022

Step 1

41 uF, C2 = 4 uF Using the formula for capacitors in series: 1/C_series = 1/C1 + 1/C2 1/C_series = 1/5.41 + 1/4 1/C_series = 0.185 + 0.25 1/C_series = 0.435 C_series = 1/0.435 C_series = 2.30 uF ** Show more…

Show all steps

Thanks for your feedback!

the capacitor c1 = 5.41 uF and c2=4 uF are connected in series. after some time, the engineer decided to connect capacitor C3 = 1.81 uF across C1 and C2. find the total charge, in uC, of the group of capacitors if they are connected across 4.87 V battery