00:01
Find the normal forces on the set of wheels in this problem.
00:04
So let's go ahead and draw our little diagram.
00:07
So we'll call this b and this point a.
00:10
So we have our normal force at a, and of course we have our normal force at b.
00:16
We also have our different distances, so that's 0 .3 meters, 0 .4, 0 .6.
00:23
And we also have this triangle, which is a 3, 4, 5 triangle at our angle theta.
00:29
From our triangle, we see sine of theta is 3 fifths, and cosine of theta is 4 fifths.
00:37
Now we have no acceleration, so the net force in our y direction is equal to 0.
00:42
In our y direction, we have our normal force a plus our normal force b equal to 100 times sine of theta plus our weight force...