00:02
Hi there.
00:03
In this question, we are given the eileen molecule, which has three carbons that are double bonded, and each of the terminal carbons has two hydrogens on them.
00:22
Okay, so the structure would look like this, in two dimensions, at least.
00:30
So the first thing we want to do is hybridize each carbon atom, or determine the hybridization of each carbon atom, rather.
00:36
So i'm going to number these, one, two, and three.
00:41
So for carbon one, we see that it has three atoms bonded to it and zero lone pairs.
00:59
Well, that means that it needs a total of three equal energy orbitals.
01:15
And an equal energy orbital, we get those by hybridization.
01:20
So we need three hybrid orbitals.
01:23
The way we can get three hybrid orbitals is by blending the s -orbitals.
01:27
Orbital and two of the p orbitals.
01:30
So this first carbon is going to have sp2 hybridization.
01:38
Right, let's look at carbon two.
01:41
Carbon two has two atoms bonded to it and zero loan pairs.
01:54
That means it needs a total of two equal energy orbitals or two hybrid orbitals.
02:05
And that means it's just going to blend its s orbital with one of its p orbitals, giving it sp hybridization.
02:16
And then carbon three.
02:18
Carbon three is going to be just like carbon one...