Question

The charged pion $\pi^{-}$ usually decays into a muon and a neutrino, $$ \pi^{-} \rightarrow \mu^{-}+\bar{\nu}_{\mu} $$ but occasionally into an electron and a neutrino, $$ \pi^{-} \rightarrow \mathrm{e}^{-}+\bar{\nu}_{\mathrm{e}} $$ The relative frequency of the electron decay (compared to the muon decay) is on the order of 1 in $10^{4}$. The large difference between the probabilities for these two decays can be explained in terms of the $\mu-\mathrm{e}$ mass difference as follows: The theory of weak interactions predicts that the probability for either decay is proportional to $(1-v / c)$, where $v$ is the speed of the outgoing $\mu^{-}$ or $\mathrm{e}^{-} .$ Calculate the quantity $(1-v / c)$ for each decay, and compute their ratio. Note that this ratio has the same order of magnitude as the observed relative frequency. (Use the result of Problem 2.40; $m_{\pi} \approx 140, m_{\mu} \approx 106$, and $\left.m_{\mathrm{e}} \approx 0.51 \mathrm{MeV} / c^{2} .\right)$

          The charged pion $\pi^{-}$ usually decays into a muon and a neutrino,
$$
\pi^{-} \rightarrow \mu^{-}+\bar{\nu}_{\mu}
$$
but occasionally into an electron and a neutrino,
$$
\pi^{-} \rightarrow \mathrm{e}^{-}+\bar{\nu}_{\mathrm{e}}
$$
The relative frequency of the electron decay (compared to the muon decay) is on the order of 1 in $10^{4}$. The large difference between the probabilities for these two decays can be explained in terms of the $\mu-\mathrm{e}$ mass difference as follows: The theory of weak interactions predicts that the probability for either decay is proportional to $(1-v / c)$, where $v$ is the speed of the outgoing $\mu^{-}$ or $\mathrm{e}^{-} .$ Calculate the quantity $(1-v / c)$ for each decay, and compute their ratio. Note that this ratio has the same order of magnitude as the observed relative frequency. (Use the result of Problem 2.40; $m_{\pi} \approx 140, m_{\mu} \approx 106$, and $\left.m_{\mathrm{e}} \approx 0.51 \mathrm{MeV} / c^{2} .\right)$
        
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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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The charged pion $\pi^{-}$ usually decays into a muon and a neutrino, $$ \pi^{-} \rightarrow \mu^{-}+\bar{\nu}_{\mu} $$ but occasionally into an electron and a neutrino, $$ \pi^{-} \rightarrow \mathrm{e}^{-}+\bar{\nu}_{\mathrm{e}} $$ The relative frequency of the electron decay (compared to the muon decay) is on the order of 1 in $10^{4}$. The large difference between the probabilities for these two decays can be explained in terms of the $\mu-\mathrm{e}$ mass difference as follows: The theory of weak interactions predicts that the probability for either decay is proportional to $(1-v / c)$, where $v$ is the speed of the outgoing $\mu^{-}$ or $\mathrm{e}^{-} .$ Calculate the quantity $(1-v / c)$ for each decay, and compute their ratio. Note that this ratio has the same order of magnitude as the observed relative frequency. (Use the result of Problem 2.40; $m_{\pi} \approx 140, m_{\mu} \approx 106$, and $\left.m_{\mathrm{e}} \approx 0.51 \mathrm{MeV} / c^{2} .\right)$
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00:01 So here in this question we are given that pi inverse plus p is gives to pi not plus n plus pi inverse minus plus pi plus and next we are given that pi plus pi dash will give rise to p plus p plus p dash so from here we have to determine the baryan numbers of the reactants and the product that are required here so for this we can say that the net number of the two reactants is 0 plus 1 that will be equals to 1 and the net variant number is the 4 products of 0 plus 1 plus 0 plus 0 is equal to 1 since the net variant number of the reactant and the product are equal so net number of reactant and product are equal then we can say that the reaction is allowed on the basis of these numbers number conservation low so according to this we can say that the net number of the reactant that is 1 plus minus 1 that will be equals to 0 and that net number of the reactant this is for the reactant and the net number for the product is 1 plus 1 plus minus 1 that will be equals to 1 since the net number of the reactant and product are not equal then reaction cannot of god...
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