00:01
We'd like to calculate the value of r s.
00:04
We're given our input voltage vi is 25 volts, v0 is 10 volts, rl is 2 kilo -ooms, and i -min is equal to 5 millie amps.
00:19
Now, for calculating r, we know is is equal to i -min plus i -mucer, max.
00:29
But i -crosser -inductor max is equal to v0 over rl, or 10 over 2, which is just 5 milli -amps.
00:39
And i -s is 10 -mli -amps, so rs is 25 minus 10 divided by 10, which is 1 .5 kilo -homes.
00:49
Now for b, we'd like to find the change in load voltage.
00:56
If it's increased by 20%, then v -n, is 25 plus 0 .20, which is 25 .2 volts.
01:06
So now v is equal to vn times r crosser inductor, divided by rl plus rs, which is 25 .2 times 2, divided by 2 plus 1 .5, to get 14 .4, which is greater than vz.
01:23
So our v .0 is 10 volts...