00:01
Hello students for the first question we have to find the equivalent resistance of the circuit.
00:06
So first we have to solve this circuit this r3 and r4 becomes parallel series.
00:15
So here rs is equal to r3 plus r4 and here r2 and rs will be in parallel.
00:26
So rp is equal to or we can write rp is equal to r2 parallel to rs that is r3 plus r4 and now the equivalent resistance r equivalent is equal to r1 plus rp plus the internal resistance r.
00:57
So first for the case rs is equal to 8 ohm and rp will give 6 ohm and r equivalent will give 8 ohm.
01:18
So req is equal to 8 ohm.
01:22
So the total resistance in the circuit is 8 ohm that is given in option c and for the second question we have to find the current that flows to the resistance 1.
01:37
So by ohm's law v is equal to ir.
01:40
Here the voltage drop across the r1 is equal to voltage drop across the terminals of battery.
01:47
So here i1 is equal to v by r1.
01:53
So 18 by 2 will give 9 ampere and the third question the current that flows through r2.
02:04
So here v is equal to i2 r2...