Question

The combustion of methanol is shown by the final equation: 2 CH3OH(l) + 3 O2(g) = 2 CO2(g) + 4 H2O(g) What mass of water could be heated from 20.0°C to 35.0°C by the burning of 2.57 mol of methanol?

Name: the combustion of methanol is shown by the final equation 2 ch3ohl 3 o2g 2 co2g 4 h2og what mass of water could be heated from 200c to 350c by the burning of 257 mol of methanol
Uploaded: 2023-07-31T16:44:55-08:00
Duration: 3 min 31 s
Channel: David Collins
Description: the combustion of methanol is shown by the final equation 2 ch3ohl 3 o2g 2 co2g 4 h2og what mass of water could be heated from 200c to 350c by the burning of 257 mol of methanol

          The combustion of methanol is shown by the final equation: 
2 CH3OH(l) + 3 O2(g) = 2 CO2(g) + 4 H2O(g)

What mass of water could be heated from 20.0°C to 35.0°C by the burning of 2.57 mol of methanol?

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Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert David Collins

07/31/2023

Step 1

The heat of combustion of methanol is -726 kJ/mol. Since we have 2.57 mol of methanol, the total heat released is -726 kJ/mol * 2.57 mol = -1866.82 kJ. Show more…

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The combustion of methanol is shown by the final equation: 2 CH3OH(l) + 3 O2(g) = 2 CO2(g) + 4 H2O(g) What mass of water could be heated from 20.0°C to 35.0°C by the burning of 2.57 mol of methanol?