Question

The combustion of octane, C8H18, proceeds according to the reaction shown. 2 C8H18(l) + 25 O2(g) ? 16 CO2(g) + 18 H2O(l) If 3.70 × 10^2 mol of octane combusts, what volume of carbon dioxide is produced at 32.0 °C and 0.995 atm? V = L

          The combustion of octane, C8H18, proceeds according to the reaction shown.

2 C8H18(l) + 25 O2(g) ? 16 CO2(g) + 18 H2O(l)

If 3.70 × 10^2 mol of octane combusts, what volume of carbon dioxide is produced at 32.0 °C and 0.995 atm?

V = L

The combustion of octane, C8H18, proceeds according to the reaction shown.

2 C8H18(l) + 25 O2(g) ? 16 CO2(g) + 18 H2O(l)

If 3.70 × 10^2 mol of octane combusts, what volume of carbon dioxide is produced at 32.0 °C and 0.995 atm?

V = L

Added by Alejandra N.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Susan Hallstrom

11/14/2022

Step 1

Given: 3.70 x 10^2 mol of octane Using the mole ratio from the balanced equation: 2 moles of octane produce 16 moles of CO2 Therefore, moles of CO2 produced = 3.70 x 10^2 mol x (16/2) = 3.96 x 10^3 mol ** Show more…

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The combustion of octane, C8H18, proceeds according to the reaction shown. 2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l) If 3.70×102 mol of octane combusts, what volume of carbon dioxide is produced at 32.0 ∘C and 0.995 atm?