The combustion of propane (C3H8) produces CO2 and H2O: C3H8 (g) + 5 O2 (g) → 3 CO2 (g) + 4 H2O (g) How many moles of CO2 can be produced when 2.5 mol of O2 and 4.6 mol of C3H8 are reacted together?
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C3H8 (g) + 5 O2 (g) → 3 CO2 (g) + 4 H2O (g) Show more…
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Propane (C3H8) reacts with oxygen in the air to produce carbon dioxide and water. C3H8 (g) + 5 O2 (g) → 3 CO2 (g) + 4 H2O (g) C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(g) Given the following balanced chemical equation, if you consumed 0.642 moles of C3H8 in the reaction, how many moles of CO2 would be made?
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The combustion of propane (C3H8) produces CO2 and H2O: C3H8 (g) + 5O2 (g) --> 3CO2 (g) + 4H2O (g) The reaction of 2.5 mol of O2 with 4.6 mol of C3H8 will produce _____ mol of H2O How did you get your answer?
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