The complete combustion of propane, C3H8(g), is represented by the following unbalanced equation C3H8 (g) + O2 (g) -> CO2 (g) + H2O (l) DH = -2220 kJ How much heat, in kJ, is evolved by the complete combustion of 1.100g C3H8, (g)?
Added by Jose S.
Step 1
100 g. To do this, we need the molar mass of propane: $$Molar\ mass\ of\ C_3H_8 = 3(12.01\ g/mol) + 8(1.01\ g/mol) = 44.11\ g/mol$$ Now, we can find the number of moles of propane: Show more…
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