00:01
Hello everyone, let us do the following question.
00:02
Here we have a three -phase line has an impedance of 1 plus j3 -oom per phase.
00:07
The line feeds a balance delta -connected load which observe a total complex power of 12 plus j5 kilowoltspire.
00:14
If the line voltage at the load has a n magnitude of 240, we have to calculate the power factor.
00:21
We have to calculate the power factor.
00:23
Here we will say for a delta -connected load.
00:30
We will solve for a delta connected load we have bp is equal to vl and il is equal to under the root 3 into ip also we know that s is written as under the root 3 vl into il from this it will find il this is written as s under the root 3 into vl it will put value for s from the question this is a 12 square plus 5 square into 10 raised to power 3 divided by under the root 3 into 240.
01:10
After we will solve, we will get 31 .273.
01:14
31 .273.
01:17
Next, it will solve 4 at the source.
01:22
Next, it will solve 4 at the source.
01:27
We will say bl dash is equal to vl plus il into j i jl plus i jl plus il into j1 so we'll put vl dash this is 240 into 0 degree plus 2 into 31 point 273 1 plus j3 after solving we will get 240 plus 62 point 546 plus j 187 .638.
02:07
So if for vl dash, we will get the value as 356 volt.
02:14
356 volt...
