Question

Determine the magnitude of F. Express your answer to two significant figures and include the appropriate units. ?A F = Value Units Submit Request Answer Part B ? Determine the component of F along line bb. Express your answer to two significant figures and include the appropriate units. ?A F = Value Units ?

          Determine the magnitude of F.
Express your answer to two significant figures and include the appropriate units.
?A
F = Value Units
Submit Request Answer
Part B
?
Determine the component of F along line bb.
Express your answer to two significant figures and include the appropriate units.
?A
F = Value Units
?
        
Show more…
Determine the magnitude of F.
Express your answer to two significant figures and include the appropriate units.
?A
F = Value Units
Submit Request Answer
Part B
?
Determine the component of F along line bb.
Express your answer to two significant figures and include the appropriate units.
?A
F = Value Units
?

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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The component of force F acting along line aa is required to be F_(a)=40lb. (Figure 1) Figure Determine the magnitude of F. Express your answer to two significant figures and include the appropriate units. (â—»^(â—»))/(b)ar (â—»),mu angstrom F= ? Request Answer Part B Determine the component of F along line bb. Express your answer to two significant figures and include the appropriate units. Determine the magnitude of Express your answer to two significant figures and include the appropriate units UA F= Value Units Submit Request Answer Part B Determine the component of F along line bb Express your answer to two significant figures and include the appropriate units. F= Value Units
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Transcript

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00:01 Today the question we are solving here is the component of a force f acting along line aa is required to be 40 lb.
00:12 So we have to determine the magnitude of f in lb.
00:16 So here by using the law of cosines to determine the components we get 40 lb by sine 80 degree that is equals to taking fbs sign as sine 60 degree divided by that will give fb is equal to 40 lb by sign 80 degree into sign 60 degree so that is approximately equals to 12 .267...
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